Speed of a satellite in circular orbit orbital velocity period centripetal force physics problem duration.
Calculate the height of geostationary satellite from the earth s ground level.
It maintains the same.
A minimum of three satellites are needed to cover the entire earth super synchronous orbit is a disposal storage orbit above gso.
Shows how to calculate the orbital height of a satellite above the surface of the earth.
A geostationary satellite orbits around the earth in a circular orbit of radius 3600 km.
Suspect the difference may be the result of different values used for g m earth and radius earth.
An object in such an orbit has an orbital period equal to the earth s rotational period one sidereal day and so to ground observers it appears motionless in a fixed.
A geostationary equatorial orbit geo is a circular geosynchronous orbit in the plane of the earth s equator with a radius of approximately 42 164 km 26 199 mi measured from the center of the earth.
Spreadsheet uses 6 674e 11 m3 kg sec2 5 972e 24 kg 6437e 06 m.
B calculate the height at which the satellite orbits above the surface of the earth.
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Nasa s aqua satellite for example requires about 99 minutes to orbit the earth at about 705 kilometers up while a weather satellite about 36 000 kilometers from earth s surface takes 23 hours 56 minutes and 4 seconds to complete an orbit.
156 a satellite in such an orbit is at an altitude of approximately 35 786 km 22 236 mi above mean sea level.
The radius of the earth is 6400km and its mass is 6x10 24 kg.
The equation for orbital height is derived from newton s second law.
My results are slightly different a bit high on orbital altitude and a bit low on velocity.
Then the time period of satellite orbiting 2600 km above the earth s surface r earth 6400 km will appoximetely be.
From earth they would seem drifting in westerly direction.
A a geostationary orbit is when the satellite remains vertically above the same point on the equator at all all times and consequently has an orbital period of 24 hours.